In a class test marks obtained by 120
Web In a class test, marks obtained by 120 students are given in the following frequency distribution. If it is given that mean is 59, find the missing frequencies x and y. Marks No. … WebApr 14, 2024 · Introduction Reasons for drug shortages are multi-factorial, and patients are greatly injured. So we needed to reduce the frequency and risk of drug shortages in hospitals. At present, the risk of drug shortages in medical institutions rarely used prediction models. To this end, we attempted to proactively predict the risk of drug shortages in …
In a class test marks obtained by 120
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WebMath Statistics The following table shows the marks obtained by 120 students of class IX in a cycle test-1. Draw the more than Ogive curve for the following data : Marks 0-10 10-20 20-30 30-40 40-50 50-60 60-70 70-80 80-90 90-100 No. of 2 6. 8 20 30 22 18 4 2 students Also, find (i) The Median (ii) The Number of students who get more than 75 marks. WebApr 11, 2024 · 3.3. Cytotoxic Activity of B. micrantha 3.3.1. Cytotoxicity on RAW 264.7 Cells. Table 2 presents the results of the cytotoxicity test on RAW 264.7 macrophage cells. It emerges from this table that the aqueous and ethanol extracts had no significant activity on the RAW 264.7 macrophage cells with of μg/ml and μg/ml for aqueous and ethanol …
WebHere the average marks of 120 candidates are 35. The average marks of passed candidates are 39. The average marks of failed candidates are 15. Concept Used: Input = Output. … WebApr 3, 2024 · In a class test, marks obtained by 120 students are given in the following frequency distribution. If it is given that mean is 59, find the missing frequencies x and y. …
WebApr 7, 2024 · The total number of marks obtained by $120$ students= total number of candidates × average marks of those students=$120 \times 35 = 4200$ ... If A1A2 are the … WebThe marks obtained by 120 students in a mathematics test is given below: $$\begin {tabular} { l l } \hline Marks & No. of students \\ \hline $0-10$ & 5 \\ \hline $10-20$ & 9 \\ \hline 20-30 & 16 \\ \hline 30-40 & 22 \\ \hline 40-50 & 26 \\ \hline 50-60 & 18 \\ \hline 60-70 & 11 \\ \hline 70-80 & 6 \\ \hline 80-90 & 4 \\ \hline $90-100$ & 3 \\ …
WebThe marks obtained by 120 students in a mathematics test is given below: Dr Draw an ogive for the given distributions on a graph sheet. use a suitable scale for your ogive. use your …
Web(a) The table below gives the frequency distribution of marks obtained by a group of students in a class test. Marks 3 4 5 6 7 8 Frequency 5 x-1 x 9 4 1 (i) Find the value of x if the mean for the distribution is 5. (ii) What is the modal mark. (iii) … dynamisches arrayWebApr 8, 2024 · The following are the marks obtained by 20 students in a class-test:40,22,36,27,30,12,15,20,25,31,34,36,39,41,43,48,46,36,37,40Arrange the above data in … dynamisches assessment centerWebTake Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly. Test Yourself. ... The average marks obtained by a class of 60 students is 65. The average marks of half of the students is found to be 85. The average marks of the remaining students is: 35. 45. 55. 65. B. 45. cs271 notesWebTotal marks obtained by 8 students in class test = (12 + 14 + 16 + 18 + 20 + 10 + 11 + 19) = 120 Using the mean formula, Mean = (Sum of Observation) ÷ (Total numbers of Observations) = 120/8 = 15 Therefore, the mean of marks obtained by 8 students is 15. cs 26 easaWebMar 15, 2024 · To build the model, a survey was conducted with 120 participants. The survey consisted in the completion of a personality test and handwritten paragraphs. The study resulted in a dataset that was used to train several machine learning algorithms. It was found that the AdaBoost classifier achieved the best results followed by Random Forest. cs2700 manualWebTotal marks obtained by a class of 40 students = 65 × 40 = 2600. Total marks obtained by half of the students = 45 × 40/2 = 900. Total marks = total marks obtained by half of the students + Total marks obtained by the remaining half of the students. ⇒ 2600 = 900 + Total marks obtained by the remaining half of the students. cs-26 easaWebSolution: Class- mark = (Upper class limit-lower class limit)/2 = (150 + 140)/2 = 290/2 = 145 Thus we can create a new table with class-mark. Now with these class marks we can plot the frequency polygon as shown below. Measure of central tendency (Mean, Mode and Median) Mean: The average of number of observations given. cs 271 stanford