Web28 Jan 2024 · In an AP, if Sn = n (4n + 1), find the AP - YouTube #class10#arithmeticprogressionsIn an AP, if Sn = n (4n + 1), find the AP … WebIn the given AP, the first term is a = 7 and the common difference is d = 4. Let us assume that 301 is the n th term of AP. Then: T n = a + (n - 1)d 301 = 7 + (n - 1) 4 301 = 7 + 4n - 4 301 = 4n + 3 298 = 4n n = 74.5 But 'n' must be an integer. Hence 301 cannot be a term of the given AP. Answer: 301 cannot be a term of the given AP.
Partial sums: formula for nth term from partial sum
Web6 May 2024 · Question 1- Find the sum of first 30 terms of AP: -30, 24, -18,/.. Solution- a= -30, d= 6 = 15 [-60 + 29 (6)] = 15 [-60+174] = 15 [114] = 1710. OR. Question 1- If an AP is Sn = … WebThen n th term of AP is , Tn = Sn - Sn-1 Common difference = d = Tn - Tn-1 Calculation: We have given that, S n = 4n 2 + 5n As we know that , Tn = Sn - Sn-1 ∴ T n = ( 4 n 2 + 5 n) − [ 4 ( n − 1) 2 + 5 ( n − 1)] ⇒ T n = 8 n + 1 .... ( i ) As we know that , d = Tn - Tn-1 ⇒ d = ( 8n + 1 ) - [ 8 ( n - 1) + 1 ] ⇒ d = 8 . The correct option is 2. twiter ily
[Solved] If the sum of n terms of AP is, Sn = 4n2 + 5n , th - Testbook
WebIf S n, the sum of first n terms of an AP is given by Sn = 3n 2 - 4n, find the nth term. Advertisement Remove all ads Solution We have, S n = 3n 2 - 4n for n = 1 ⇒ S 1 = 3 ( 1) 2 - 4 ( 1) = 3 - 4 = - 1 ⇒ a 1 = S1 = -1 for n = 2 ⇒ S 2 = 3 ( 2) 2 - 4 ( 2) = 12 - 8 = 4 S 2 = 4 a 2 = S 2 - S 2 = 4 - (-1) a 2 = 5 Common difference, d = a 2 - a 1 WebIf S n the sum of first n terms of an AP is given by S n=3n 2−4n, find the n th term. Medium Solution Verified by Toppr Given Sum of n terms is S n=3n 2−4n So Sum of n−1 terms is S … WebThis is the formula to find the nth term of an AP a n = S n + S n + 1 So you can get a 1 = 5 a 2 = 9 a 3 = 13 Thus the common difference is 4 Share Cite Follow edited Dec 20, 2024 at 15:55 answered Dec 20, 2024 at 13:52 Naimisha Girish 1 4 … taking links out of watch band